057.Insert Interval

Posted on | In

Solution 1: accepted 21ms

Add the new node to the list, and do the rest just like 056. 

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
public List<Interval> insert(List<Interval> intervals, Interval newInterval) {
    List<Interval> result = new ArrayList<>();
    intervals.add(newInterval);
    if (intervals.size() == 1)
        return intervals;
    Collections.sort(intervals, new Comparator<Interval>() {
       public int compare(Interval a, Interval b) {
           return a.start - b.start;
       } 
    });
    for (int i = 0; i < intervals.size() - 1; i++) {
        Interval current = intervals.get(i);
        Interval next = intervals.get(i + 1);
        if (current.end < next.start) {
            result.add(current);
        } else {
            next.start = current.start;
            next.end = Math.max(current.end, next.end);
        } 
    }
    result.add(intervals.get(intervals.size() - 1));
    return result;
}